The heat capacity Cp of water is 4.186kJ/kg-C 566 Btu's x 0.000293 kWh/Btu = 0.166 kWh. So, the energy required to raise the temperature of 7000 kg of water from 20C to 80C is: heat of vaporization of water is 2256 kJ/kg. How long would it take a kettle with a 1kW heating element to heat 1 litre of water? Straight to the point. Thank you! As 1 litre of water needs about 1.16 watts to raise it through 1°C in an hour, a 120 litre tank of cold mains water needs a total energy input of about 7800 watts-hours (120*1.16*56) to raise its temperature to the required level. Irvine) Heating a gallon of water by 1°F with no losses thus takes 8.33 ÷ 100,000 = 0.00008.33 therms. At $1.20 /therm, it costs 11.31 x $1.20 = $13.58 to heat 1000 gallons. annual and total lifetime water heating costs based on different water heating systems and energy sources. 1 Watt = 1 Joule of energy per second 1 kW = 1000 Joules of energy per second. ( Log Out / Generally, oil heats up in half the time of water, due to its density. This kind of thermal radiation is similar to feeling the heat of a campfire on your face from a distance. I am assuming calculations take into account the specific heat capacity of water? With a 3 hour design reheat time, this means a power input of about 2600 watts. At Process Heating Services, we have 2 types of customer. I think of it this way: the power limit of heating coil simply submerged in water is reached when the water starts to boil around the coil while the water in other places is still much colder. It takes 667 92.7% = 720 Btu’s to heat a gallon of water using electricity. that is impossible to calculate with the information given. Solve for Thermal Power To heat the water to boiling: E = 4.186 kJ/kgC x 0.998 kg x 76C = 317.5 kJ = 0.088 kW-hr. All help is greatly appreciated - where possible, assume 'normal' conditions, i.e., use a standard or generally accepted density for air. Only input whole numbers, do not use a comma or point. 1 Watt = 1 Joule of energy per second 1 kW = 1000 Joules of energy per second. Power = Energy / time (U.C. Sweet! That’s just an example, I have no idea how fast a tub cools down. … C p is the specific heat of water (4.186 J/gm deg C) The calculator below can be used to determine the temperature delta or rise for a given cooling water application (heat load or power dissipated and cooling water flow rate) using the first formula above. Create a free website or blog at WordPress.com. Please remember, that the calculators above assume 100% conversion efficiency. One kilo calorie is the amount of heat needed to raise the temp. This means that you will have to pay 23 €ct to heat the bathwater with electricity and and 12 €ct to heath with gas if you take a bath (exlusive watercosts). There are others who need guidance and advice as to what they need. I'm under the impression that a Calorie (kcal) heats one liter of water by one degree, and so heating one liter by 35 degrees requires 35 Calories. • The heat content of one gallon of fuel oil roughly equals that of 41 kWh of electricity, 137 cubic feet of natural gas, 1.5 gallons of propane, 17.5 pounds of air-dried wood, 17 pounds of pellets, a gallon of kerosene, or 10 pounds of coal. The following formula is used to calculate the power of heating element needed to heat a specific volume of water by a given temperature rise in 1 hour. I want to convert this to Watthours but I'm not sure how....does bringing time into the equation determine how much energy I need to expend? Your calculators are a big help in figuring the size of the heat sump. The calculators use the specific heat capacity of water of 4186 J/kg/°C (Joules per kilogram per degree Celsius). Hot water cylinders/tanks come in many shapes, sizes and capacities, ranging from 40 to over 400+ litres in larger homes. Specific heat capacity of water kcal/kgx°C 3: 1. An I missing something here? It would be really cool to see a calculator that takes this new technology into account. Let's call that 92.7% on average. One kWh is 3413 Btu's, so one Btu is 1/3413 = 0.000293 kWh. We normally see energy in our electricity meter and bill as kilo-watt hours, rather than kilo-joules, so we have to divide by 3,600 (the number of seconds in an hour) to convert them — so 18,900 KiloJoules is 5.25 kilowatt-hours (18900 ÷ 3600 = 5.25) So basically I use 5.25 electricity credits every day heating up water. Volume of fluid to heat in litres: Starting temperature degrees C: Target temperature (finishing) degrees C: Heating power kW: Density of water kg/dm 3: 1. time required to reach target temperature at given power: hours heat of fusion of ice is 334 kJ/kg. If you have problems with the units, feel free to use our temperature conversion or weight conversion calculators. ( Log Out / One gallon of gasoline (petrol) is about 118,000 BTU. What formula did you use to calculate the water heating power? There are those who tell us what they want as they know their exact requirements. A kilocalorie (C) is the amount of energy needed to heat 1 liter (1000 milliliters or 1000 cubic centimeters) of water one degree centigrade. 1 to heath one liter of water … And as always, double check with some other source and my help is without any guarantee or similar. Heating water to have a bath can be a major cost on your energy bills depending on how you heat the water and how much water you use. Change ), You are commenting using your Facebook account. water-related energy use is at least 521 million MWh a year—equivalent to 13% of the nation’s electricity consumption. The power in watts is then found by: energy (joules) / time (seconds) To convert that answer to kilowatts, divide by 1000. of 1kg water by 1˚C . For less than the price of a new heater tank, I now have free hot water. Labels: energy savings, math. Heating oil provides 138,500 British thermal units (BTU) per US gallon; 1 BTU = 0.000293 kWh; 1 US gallon = 3.78541178 litres (138,500 * 0.000293)kWh in 3.78541178 litres (138,500 * 0.000293)/3.78541178 kWh/litre = 10.720233982047786621512547837002 A 60 watt light bulb uses 60 watt-hours of energy in one hour. Calculate the kilowatt-hours (kWh) required to heat the water using the following formula: Pt = (4.2 × L × T) ÷ 3600. This calculator is great. Change ), You are commenting using your Google account. One Btu is 0.000293 kWh. Appreciate the calculators but i was wondering if you could tell me the exact equations used for the “Water Heating Energy Calculator” or give some sort of excel sheet to double check it. It takes 667 92.7% = 720 Btu’s to heat a gallon of water using electricity. So it takes 525 ÷ 92.7% = 566 Btu's to heat a gallon of water in an electric tank. So, this is 12.8889 kWh/liter of heat energy. It also should be noted that the difference between the starting temperature and the desired final application temperature is commonly referred to as delta T (ΔT). Improved calculators that support comma, dot, and efficiency, are available here: time, energy, and power. In the United States, the most commonly used value for expressing the energy value or heat content of a fuel is the British thermal unit (Btu). Change ), You are commenting using your Twitter account. 1kWh = 1000W x 3600s = 3.6MJ. The specific heat of water is 4186 Joules/kg-C. Heating oil provides 138,500 British thermal units (BTU) per US gallon; 1 BTU = 0.000293 kWh; 1 US gallon = 3.78541178 litres (138,500 * 0.000293)kWh in 3.78541178 litres (138,500 * 0.000293)/3.78541178 kWh/litre = 10.720233982047786621512547837002 The higher element usually is for when you need to heat some water in middle of day. Also, you should have some extra power available, just to be sure. specific heat of steam is 2.1 kJ/kgK. The calculators cannot handle points or commans, only whole numbers. I’m curious, though. Nice calculator buttt…… you’ve got the abbreviations for the metric units incorrect. Let’s make a calculation example for a tub with 250 us gallons that cools down from 105f to 103f in 2 hours. Density: 1000 kg / m 3 or 1 kg / litre This is a measure of the mass (weight) of a set volume of water. Hi “New pool, cold water !” ie, the metal kettle on the gas hob, would loose more water temperature, than say the plastic, electric kettle, as plastic is a better heat retainer than metal. There are many other factors including the temperature of the cold water entering the heater system, the temperature of the hot water coming out of the heater and hot taps and the cost per kWh of the energy. The energy stored in the water tank can be calculated as. M = 7 meter cube = 7000 Ltrs or 7000 Kg Pt is the power used to heat the water, in kWh. This calulator tells you how much minimum heating power is required to heat the water within a specified amount of time. Energy E = m•Cp•ΔT = 7000 x 4.186 x 60 = 1758120 kJ Roughly speaking, due to its density and viscosity, heavy oil will heat up in half the time of water, or if you prefer, require around half the heating power to heat up the same volume of water in the same period of time. It takes about 1/10 kWh of energy to boil a litre of water and around 5kWh to heat a bath. Boil or evaporate? There's a great answer about heating water with electricity, where anyone can easily get an idea how much would it cost to heat water just by applying one's price for kWh. Often, energy is measured in kWhs So 78 C rise requires 326,508 Joules per kg. Also we can use this formula as the basis of similar calculations for heating oil. 3412 BTU = 1 kWh. This calculator tells you how long it takes to heat water from start to end temperature with a given heating power. The answer is 6 hours 24 minutes. I am tasked to maintain a 110L aquarium at 22-24C outdoors in Texas. A litre of water at 25℃ needs a certain amount of calories to become steam at 100℃ ∆t=75℃ (75Kcal + 540Kcal =615Kcal) if I remember the figures. I have done the calculations in the calculator above for heating 33’000 US gallons from 68F to 90F in 5h (300min) and got a result of approximately 1’200’000 btuh. The increase in temperature is 45 Kelvin (60-15) So the energy needed is 180,000 x 45 x 4.2 = 34MJ. This is why the calculators complain in these situations. How much heat energy in joules is necessary to raise the temperature Of 7000 kg (7 M3) of water from 20 °C to 80 °C? 1kcal=1000cal. The surrounding temperature (where the energy can be transferred to) is 20oC. meaning that the water would be heated in 1 hour by 3.5kW of applied heat. Wouldn’t it be faster in the latter case, because the water flow would exchange heat more efficiently than just by convection? And 1 calorie equals 4,184 Joule. K). natural gas, or kilowatt hours or electricity (kWh). I am guessing its q=m*cp*dt but when I do the calcs by hand, i get something off so i would like to know my mistake, How much heat energy in joules is necessary to raise the temperature Of 7000 kg (7 M3) of water from 20 °C to 80 °C? 180 litres of water is near enough 180kg. Specific Heat Capacity: 4200 J / kg / C This is a measure of the amount of energy, measured in Joules, required to heat water. , As another calculator for us math dummies could be total kw x cost of electrical supply. ( Log Out / The immersion stat will control temperature which will normally be well under boiling point - so 65 degrees or so, depending on what it is set at. As 1 litre of water needs about 1.16 watts to raise it through 1°C in an hour, a 120 litre tank of cold mains water needs a total energy input of about 7800 watts-hours (120*1.16*56) to raise its temperature to the required level. As for efficiency, an electrical water heater can convert electricity with almost 100% efficiency to heat that can be transferred to the water. One kWh is 3413 Btu’s. Thanks! Hi Larry, the energy that is used to heat water from 40 degrees to 60 is the same amount that is lost when the water cools down from 60 to 40 (only changed sign). EDIT: My gas is billed in 15kg gas cylinders, but feel free to allow for liters of gas. That means that for every 10 litres of hot water you use will only cost you 7 cents. meaning that the water would be heated in 1 hour by 3.5kW of applied heat. Heat capacity formula. This way a circulation develops in the water container given the shape of the water container permits it. The insulation of where the heating device sits and whether any heat can escape into something other than the water (like a wall, concrete etc.) With a 3 hour design reheat time, this means a power input of about 2600 watts. So they may complain when you input commas or points. Great calculator. Last updated on April 16th, 2020. is there a formula to calculate the temperature required for 5 gallons of water that will increase the temperature of a stainless steel 15.5 gallon tank from 46F to 161F. I am looking for how much energy is need to maintain water temperature. This is the best set of calculators on the internet . This means that you will have to pay 23 €ct to heat the bathwater with electricity and and 12 €ct to heath with gas if you take a bath (exlusive watercosts). I'm heating a liter of water from 25C to 60C. If we only have a 1kW element available, we will expect a heat up time in excess of 3 hours. is more important for efficiency. One kWh is 3413 Btu’s. At $0.11/kWh, it costs 6.63 x $0.11 = $0.73 to heat a 40-gallon tank." They are also measured by heat content. volume in litres x 4 x temperature rise in degrees centigrade / 3412, (4 being a factor and 3412 being a given constant), for example 100 litres of water, to be heated from 20ºC to 50ºC, giving a temperature rise of 30ºC would give –. Cost of 1 litre of hot water according to appliance type . Often, energy is measured in kWhs 1 litre for 1 degree in 1hour is 1,16 kW/h. Fill in your details below or click an icon to log in: You are commenting using your WordPress.com account. To heat the same water volume in half the time (30 minutes) would need twice the heating power, ie, 7kW. 1758120 kilojoule/hour = 488.36666667 kilowatt hour If you want to boil it and turn it all completely into steam, you'll need another 0.7421 kilowatt-hour 1 kilowatt hour (kWh) = 3.6 megajoules 1 megawatt hour (MWh) = 3.6 gigajoules 1 kJ = 0.278 Wh 1 MJ = 0.278 kWh 1 GJ = 278 kWh 1 TJ = 278 MWh 1 PJ = 278 GWh 1 kWh = 3.60 MJ 1 calorie (c) = 4.19002 Joules Note 1 calorie is (approximately) the amount of heat required to raise the temperature of one ml of water by 1 degree Celsius. This is also The value of the specefic heat of water. L is the number of liters of water that is being heated and T is the difference in temperature from what you started with, listed in degrees Celsius. Heating water to have a bath can be a major cost on your energy bills depending on how you heat the water and how much water you use. Heating a full 184 litre (40g) tank costs $1.33 and $2.01 for a 279 litre (60g) tank. The calculators support Celcius/Centigrade, Fahrenheit, Watts (w), Kilowatts (Kw), Btuh, Joule, British termal unit (Btu), liter, gallon, kg, lb, cubic inch, cubic foot etc. how to calculate power required to heat water. You used 0.001163 of one kilowatt-hour to heat your liter of water from 0°C to 1°C. Heating a gallon of water by 1°F with no losses thus takes 8.33 lbs x 1 Btu/lb = 8.33 Btu's. it takes the same amount of energy to heat water from 48 degrees to 52 degrees as it takes to heat water from 58 degrees to 62. For Heating Water in Tanks: KW = Liters x Temperature Rise (°C) 790 x Heat-up Time (hrs.) The calculators assume 100% efficiency and no loss of energy during the heating process. When using a simple coil submerged in water, then it will start to heat the water just around it. Last edited: Jun 16, 2016. That is a 1 ATM. watts) to water. A simple formula to estimate the energy required to heat a volume of water is : E = C*V*DeltaT/PR Where E = energy in kWh C = Specific heat of water - 4.187 kJ/kgK, or 1,163 Wh/kg°C V = volume of water to heat deltaT = Th-Tc Th = temperature of hot water The higher element usually is for when you need to heat some water in middle of day. = (294000 kWs) (1/3600 h/s) = 81.7 kWh. And for testing/sampling the cool-down, measure a larger drop in temperature, such as 10f, else the result will be unreliable (reading 1f or 2f changes off a small thermometer may be very inaccurate). Thats $0.01275 per gallon for gas and $0.01825 per gallon with electric. They are saying the modern heat pumps can give you 3.8 watts worth of hot water (or something close to that) for each watt that the heat pump uses. Great help to calculate water flow and energy consumption! specific heat of ice is 2.06 kJ/kgC. 488 kwh for 1 hour One Btu is 0.000293 kWh. @Anna of 1g water by 1˚C . Hi John, For 4 hours 488/4 = 122kw Specific heat capacity of water kcal/kgx°C 3: 1. Cost To Heat Water Using Electricity A typical electric water heater is 90.4 to 95% efficient or 92.7% average efficiency. EDIT: My gas is billed in 15kg gas cylinders, but feel free to allow for liters of gas. To determine BTU lost can I use the “Water Heating Energy Calculator” only backwards? To heat the same water volume in half the time (30 minutes) would need twice the heating power, ie, 7kW. Also, the calculator is only correct in the theoretical case that while the water is being heated, no heat escapes from the water to the environment (air or walls etc.). I have saved the page to my home screen. Hence, the energy needed is 34/3.6 = 9.5 kWh. How to calculate the kW required to heat a volume of water in a particular time. I’ve been looking for a simple way to ballpark the size of a solar thermal hot water system – and this makes it dead simple! I'm heating a liter of water from 25C to 60C. Converesely, if we only use half the heating power, 1.75kW, it will take twice as long to heat up to desired temperature, ie, 2 hours. Thermal radiation losses occur from direct sunlight, high water temperature or high relative humidity. Start temp as final and end temp as start. I do not think it makes much of a difference in practice. Thanks!!! While this appears to be a conservative estimate of water-related energy use, our findings suggest that the carbon footprint currently associated with moving, treating and heating water in the U.S. is at least 290 million Thus,mass of 1l water=1kg. So we've got 0.166 kWh to heat a gallon of water, or 0.166 x 40 = 6.63 kWh to heat a 40-gallon tank. A Watt is named after James Watt hence the abbreviation is a capital W. A thousand of something is a “kilo” for example a kilogram. Here’s a breakdown of how hot water is used in an average month. Calculation for working out factor to convert litres of heating oil into kWh / litre. If you can test how fast the water cools down in your tub, then you can calculate how much heating power is required to prevent that from happening. A typical electric water heater is 90.4 to 95% efficient. At $1.20 /therm, it costs 11.31 x $1.20 = $13.58 to heat 1000 gallons. To boil ALL the water: I’m trying to figure out what would it take to heat my pool using a heating pipe after the filtration pump. P = calculated heat transfer (kW) h e = evaporation energy of the steam (kJ/kg) The evaporation energy at different steam pressures can be found in the Steam Table with SI Units or in the Steam Table with Imperial Units. The mass of the one liter of H2 produced by a typical "HHO" scam device in one minute: .000089 kg = .089 grams = 89 milligrams. And this is 488.36 Kilo Watts of power (since 1J/s = 1W) For rocket science one might want to calcualte it more accurately. If using electric it's near enough 100% energy conversion from energy paid for to heat, but leccie is more expensive than gas per kWh (see bills). 250 us gallons at 105f with moderate insulation… would 100 watts DC heater maintain this temperature? This is the typical heat capacity of water. For Heating Water in Tanks: KW = Liters x Temperature Rise (°C) 790 x Heat-up Time (hrs.) Thermal radiation losses are responsible for 20%-30% of heat energy loss in the swimming pool. 1 meter cube = 1000 Ltrs Water at room temperature 22 C must be raised to 100 C and heat of vaporisation added to become a gas. Calculation for working out factor to convert litres of heating oil into kWh / litre. It complains when volume is 0.25 US gallon, saying volume must be greater than zero. Problems with limit calculations: It complains if the end temp is 212°F or even 211°F, saying it must be less than boiling. I am wondering though, doesn’t heat capacity increase with temperature, potentially throwing off the calculation? Running a bath will use approximately 60 - 80 litres of water. It is the way it is taught at school. Our updated website is up, running and ready for viewing. The specific heat capacity of water is approx 4.2 J / g.K. I know that "both heat of vaporization plus the heat required to raise the water to 100°C" but the energy required to raise the water to 100°C contributes just 5% of the total requirement . 1) thermal transfer from heat source to water 2) As the water is heating up, the loss of water temperature due to conduction to the cooler surrounding air. I'm looking for the same calculation, but for gas. I entered 688 litres start temperature 29 C end temp 37 C with 1600 watts of power. The two keys they had were that it cost $0.51 to heat 40 gallons using gas or $0.73 using electric. 1000 watts is 1000 Joules per second, but spread over 1000 ml. The heat capacity is largely constant in the temperature range that the calculators work (34-210°F or 1-99°C). Where C p is the heat capacity of water (1 BTU/lb/F) and m is the mass of the water (Assume 1 gal has 8.3 lb of water and the 3,412 BTU = 1 kWh) Solution: Energy required for heating the water to 120°F: = m × C p × ΔT = 100 gal day × 8.3 lb gal ︸ m × 1 BTU lb °F ︸ C p × (120 − 65) °F ︸ ΔT = 100 gal day × 8.3 lb gal × 1 … There are many other factors including the temperature of the cold water entering the heater system, the temperature of the hot water coming out of the heater and hot taps and the cost per kWh of the energy. For that reason, these values are the minimum and some margin should be added to them. One therm is 100,000 btu's. For an electrical heater that can be a good assumption, but not for a gas heater. Water is heated to 90oC. Gas Engineer. To heat 1 ml of water takes 4.18 Joules per degree C, the specific heat capacity. Also we can use this information to extrapolate both ways. The calculators on this page compute how long it takes to heat water, how much energy is consumed, and how much heating power is required. The gas needed depends on your boiler, it's perhaps 60% efficient. This calculator tells how much energy will be consumed to heat the water from the start to end temperature. Hi all. This was super helpful in calculating the power needed to produce my hot water via solar photovoltaics. The amount of energy needed to raise the temperature of 1 g of water by 1 degree Celcius or (1 Kelvin) equals 1 calorie. However this will require a much lower watt density than on a oil heater. However, oil needs a much lower watts density element than water, as described in the “How to choose an oil heater” article. 1 BTU is the amount of heat required to raise the temperature of 1 pound of water 1 degree F. (1 kg x 1 degree C would be 3.96 BTU.) 1 litre of water has a mass of 1 kg. If you have problems with the units, feel free to use our temperature conversion or weight conversion calculators. But I have an idea. A BTU is the amount of energy required to heat 1 pound of water by 1°F (specifically from 39° to 40°F). is this calculation valid only when submerging the heating device in the water, or also when the water is circulating through a heating pipe using a pump? Specific Heat Capacity: 4200 J / kg / C This is a measure of the amount of energy, measured in Joules, required to heat water. ΔT = 80-20 = 60 C If you use a 611 watts heater in this example, then it will be about enough to reverse this cool-down from 105f to 103f by heating the water back up from 103f to 105f during the same period (realistically, of course, the water does not cool down, but stays at the same temperature). or = 488 .36 KW I just want to maintain the temperature. Click HERE for our online water heat up time calculation page. So one Btu is 0.00001 therms. The cost of electricity is for example 7.15 €ct per kWh and for natural gas is 28 €ct per m 3 of gas. The cost of electricity is for example 7.15 €ct per kWh and for natural gas is 28 €ct per m 3 of gas. Formula to calculate electricity or gas consumption of water heating . Thank you. I’m looking at a 50,000 btu boiler with a heat exchanger to heat a 33,000 gallon pool to 90 degrees f. I’ve run then calculation through the formula above, and it’s coming up with a 600,000 btu boiler to raise the water temp (68f) in 5 hours to 90f, which seems to be a really high number? As such, for every litre of hot water, you need to factor in: the price of a litre of water; the write-off of the purchase price and the installation cost of your domestic hot water generating system; your energy consumption to heat this litre of water. ( Log Out / at 1:57 PM. 1 to heath one liter of water it will cost one kcal, what equals 4.18 kJ.
At $0.30/kWh that's $2.85. It makes 1 out of 1.6, excellent piece of kit. Now, 1 kWh contains 3.6 MJ/kWh. One calorie is the amount of heat needed to raise the temp. I'm under the impression that a Calorie (kcal) heats one liter of water by one degree, and so heating one liter by 35 degrees requires 35 Calories. Under partial vacuum, such energy requierement can be less. There's a great answer about heating water with electricity, where anyone can easily get an idea how much would it cost to heat water just by applying one's price for kWh. Think of power as the rate at which energy is used. Time period available to heat the water (minutes), Water Heating Calculator for Time, Energy, and Power. Energy rates as of November 1, 2020. density of water is 1g/cu.cm or 1kg/cu.d. It depends how much you want to heat the water up by: As a general rule, the energy (in joules) to heat water is given by: Energy = mass of water (kg) x temperature rise (celsius) x 4200. Over an hour it would be “kWh”. This is for a hot tub, I do not need to increase or decrease the temperature. Hot water immersion heater elements are usually rated at 3 or 6 Kilowatts (kW). One kWh is 3413 Btu's, so one Btu is 0.000293 kWh. This is the typical heat capacity of water. So if you want to raise the temperature of 1 litre of water (1 litre = 1000g for water) by 80 degrees Celcius, your calculation should look like this: 1000g*4,184J/ (g*°C)*80°C= 334 720 Joules 1 kWh = 3 600 000 Joules, because 1 watt of power during 1 second equals 1 Joule. Cost To Heat Water Using Electricity A typical electric water heater is 90.4 to 95% efficient or 92.7% average efficiency. There is 3.785 liters per US Gallon so these figures are 129.45 MJ of heat energy per US Gallon which is equal to 35.96 kWh of heat energy per US Gallon. 1 C. colshaws. Also we can use this information to extrapolate both ways. The immersion stat will control temperature which will normally be well under boiling point - so 65 degrees or so, depending on what it is set at. In turn the abbreviation, for one thousand, is k. Bringing these two together, a kilowatt is a “kW”, not as you have, “Kw”. Posted on March 13th, 2016
Water Litre to kg: 1 Litre = 0.999975 kg, so for all practical purposes 1 L = 1 kg Water kg to Litre: 1 kg = 1 litre Example: LPG Gas 14.2 kg Equals How Many Liters with 75% Butane For LPG (propane) 1 kg = 1.96 L. Therefore, 14.2 kg = 27.832 L. For LPG (butane) 1 kg = 1.724 L. Therefore, 14.2 kg = 24.48 L 98°C to 102°C) this does not hold true any more. Also we can use this information to extrapolate both ways. Your immersion could be slightly faulty, or be covered with scale in some hard water areas . Volume of fluid to heat in litres: Starting temperature degrees C: Target temperature (finishing) degrees C: Heating power kW: Density of water kg/dm 3: 1. time required to reach target temperature at given power: hours 100 kcal of heat is required to raise the temp of 1 kg water from 0 ˚C to 100 ˚C. specific heat of water is 4.186 kJ/kgC. How do I calculate btu size for heating a swimming pool? -2°C to + 2°C) or from fluid to gas (e.g. 1 litre of water is 1kg for example 100 litres of water, to be heated from 20 ºC to 50 ºC, giving a temperature rise of 30 ºC would give – 100 x 4 x 30 / 3412 = 3.52 meaning that the water would be heated in 1 hour by 3.5kW of applied heat. This unit is less used than it was. As for effectiveness, a large enough pipe with a pump can probably in theory transfer more heat per second (meaning power, e.g. How much depends on the shape of your pool, the quality of the insulation of the pool, the difference of the desired water temperature to the environment and how long you are willing to wait until it is heated. Change ), heating elements, immersion heaters, and more, Watt density and its importance for brewery immersion heaters. One question which comes up time and again is “How many kW do I need to heat up my tank?”. For practical purposes, it should be precise enough. E = (4.2 kJ/kgoC) ( (90 oC) - (20 oC)) (1000 liter) (1 kg/liter) = 294000 kJ. 1 L water = 0.998 kg. Hi, I am trying to calculate the energy required to heat air that is 6.7 degrees C to 21 degrees C, in kilowatt hours, and for a range of other temperatures (5.7, 6.9, 9.5..... and many others, all to 21 degrees celsius/centigrade). Is that realistic? Example - Batch Heating with Steam . Using the “Water Heating Power Calculator” above (250 us gallons, start temperature 103f, end temperature 105f, 120min) tells us that a heating power of 611 watts is required. But when the state of water changes from solid to fluid (e.g. This is great. For 8 hours 488/8 = 61kw. May 21, 2010 #4 PaulS1950. The answer was 4 hours. I'm looking for the same calculation, but for gas. If i change the power to 1.6kw . I have done the calculation again manually in an Excel spreadsheet and got the same result. 1 litre of water is 1kg 1 meter cube = 1000 Ltrs M = 7 meter cube = 7000 Ltrs or 7000 Kg The heat capacity Cp of water is 4.186kJ/kg-C ΔT = 80-20 = 60 C Lecci is about 10p / kWh, so about 50p for a bath and 10p for a litre of tea. It very much depends on the surrounding temperature, the heat conductivity of your hot tub material, and the shape of the tub. Hot water immersion heater elements are usually rated at 3 or 6 Kilowatts (kW). If we can calculate the volume of water and the required temperaure rise, we can answer this question. Running a bath will use approximately 60 - 80 litres of water. The calculators cannot deal with dots or comma. Hot water cylinders/tanks come in many shapes, sizes and capacities, ranging from 40 to over 400+ litres in larger homes. I just recently learned about hybrid heat pump water heaters for the home that have much higher heating efficiency than standard electric. According to "latent heat of vaporization of water" it would take around 0.62 kWh/liter but I'm not sure...please help! Since water gets lighter when heated it will start to ascend around the coil and cold water will flow to the coil from below. Save my name, email, and website in this browser for the next time I comment. The volume in gallons (5), ambient temperature (46F) and target temperature (161) are variables that will change. It would be more complicated to build calculators that can handle that and I have not done so. Density: 1000 kg / m 3 or 1 kg / litre This is a measure of the mass (weight) of a set volume of water.